0 votes 0 votes The value of $$\lim_{x\to\infty}\dfrac{\sqrt{9x^2+2020}}{x+7}\:\text{is}$$ $\dfrac{7}{9}$ $1$ $3$ indeterminable Calculus gate2020-ce-2 calculus limits + – go_editor asked Feb 13, 2020 • recategorized Mar 12, 2021 by Lakshman Bhaiya go_editor 5.3k points answer See all 0 reply