A water sample is analyzed for coliform organisms by the multiple-tube fermentation method. The results of confirmed test are as follows:

$\begin{array}{|cl|cI|cI|}\hline

&\textbf{Sample size $\text{(mL)}$} & \textbf{Number of positive}& \textbf{Number of negative} \\ && \textbf{results out of $5$ tubes} &\textbf{results out $5$ tubes}\\ \hline &\text{$0.01$} & \text{$5$} & \text{0} \\ \hline &\text{$0.001$} & \text{$3$} & \text{$2$}\\ \hline &\text{$0.0001$} & \text{$1$} & \text{$4$} \\ \hline \end{array}$

The most probable number $\text{(MPN)}$ of coliform organisms for the above results is to be obtained using the following $\text{MPN}$ Index.

$\text{MPN}$ Index for Various Combinations of Positive Results when Five Tubes used per Dilution of $10.0 \text{ mL}$, $1.0\text{ mL}$ and $0.1 \text{ mL}$ |

Combination of positive tubes |
$\text{MPN}$ Index per $100$ $\text{mL}$ |

$0 – 2 – 4$ |
$11$ |

$1 – 3 – 5$ |
$19$ |

$4 – 2 – 0$ |
$22$ |

$5 – 3 – 1$ |
$110$ |

The $\text{MPN}$ of coliform organisms per $\text{100 mL}$ is

- $1100000$
- $110000$
- $1100$
- $110$