in Quantitative Aptitude recategorized by
2 votes
2 votes

​​​​​​$\bigoplus$ and $\bigodot$ are two operators on numbers $\text{p}$ and $\text{q}$ such that $p \bigoplus q=\dfrac{p^{2}+q^{2}}{pq}$ and $p \bigodot q=\dfrac{p^{2}}{q}$;

If $x\bigoplus y=2\bigodot 2$, then $x=$

  1. $\frac{y}{2}$
  2. $y$
  3. $\frac{3y}{2}$
  4. $2y$
in Quantitative Aptitude recategorized by
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1 Answer

1 vote
1 vote
Best answer
Given that, $p \bigoplus q=\dfrac{p^{2}+q^{2}}{pq},p \bigodot q=\dfrac{p^{2}}{q}$

Performing these operations we get,

$x \bigoplus y = 2 \bigodot 2$

$\implies \dfrac{x^{2} + y^{2}}{xy} = \dfrac{2^{2}}{2}$

$\implies \dfrac{x^{2} + y^{2}}{xy} = 2$

$\implies x^{2} + y^{2} = 2xy$

$\implies x^{2} + y^{2} – 2xy = 0$

$\implies (x-y)^{2}= 0$

$\implies x = y$

So, the correct answer is $(B).$
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