0 votes 0 votes The value of $\int_0^{\infty} \dfrac{1}{1+x^2} dx + \int _0^{\infty} \dfrac{\sin x}{x} dx$ is $\dfrac{\pi}{2} \\$ $\pi \\$ $\dfrac{3 \pi}{2} \\$ $1$ Calculus gate2016-ce-1 calculus definite-integral + – Milicevic3306 asked Mar 27, 2018 • recategorized Mar 11, 2021 by Lakshman Bhaiya Milicevic3306 11.9k points answer See all 0 reply