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A square pyramid has a base perimeter $x$, and the slant height is half of the perimeter. What is the lateral surface area of the pyramid?

  1. $x^{2}$
  2. $0.75 \: x^{2}$
  3. $0.50 \: x^{2}$
  4. $0.25 \: x^{2}$

2 Answers

Best answer
17 17 votes

Given, perimeter of a pyramid is $x,$ so slant height is $\dfrac{x}{2}.$

Lateral Surface Area of a pyramid

$= \dfrac{1}{2} \times \text{perimeter}\times \text{slant height}$
$= \dfrac{1}{2} \times x \times \dfrac{x}{2}$
$= 0.25 x^{2}$

so option D is correct .

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1 1 vote

 

  • Simple way to solve it is [ without having any formula ] 
  • We know that pyramid is nothing take a square as base and on top of that put 4 triangles and it is a square 
  • Total surface area = Area of square +. 4 triangles area 
  • But question is about lateral surafe area, which means we don't include area of square which is base 
  • Now what is area of one triangle = 1/2 * base * height  [ to get final answer just multiply by 4 ] 
  • It is given that base of perimeter is x so single base is x/4 [ because square 4 sides ] 
  • Now height they said x/2 
  • So Final answer = 4 * [ 1/2 * x/4 * x/2 ] = x^2 / 4 = 0.25 x^2 

 

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