Uniform flow with velocity $U$ makes an angle $\theta$ with $y$-axis, as shown in the figure

The velocity potential $(\phi)$, is

- $\pm U(x\sin\theta+y\cos\theta)$
- $\pm U(y\sin\theta-x\cos\theta)$
- $\pm U(x\sin\theta-y\cos\theta)$
- $\pm U(y\sin\theta+x\cos\theta)$