The number of trains and their corresponding speeds for a curved Broad Gauge section with $437 \mathrm{~m}$ radius, are
- $20$ trains travel at a speed of $40 \mathrm{~km} / \mathrm{hr}$
- $15$ trains travel at a speed of $50 \mathrm{~km} / \mathrm{hr}$
- $12$ trains travel at a speed of $60 \mathrm{~km} / \mathrm{hr}$
- $8$ trains travel at a speed of $70 \mathrm{~km} / \mathrm{hr}$
- $3$ trains travel at a speed of $80 \mathrm{~km} / \mathrm{hr}$
If the gauge (center-to-center distance between the rail heads) is taken as $1750 \mathrm{~mm}$, the required equilibrium cant (in $\mathrm{mm}$ ) will be $\_\_\_\_\_\_\_$ (rounded off to the nearest integer).