edited by
0 votes
0 votes

​​​​​A homogeneous shaft $\text{PQR}$ with fixed supports at both ends is subjected to a torsional moment $\mathrm{T}$ at point $\mathrm{Q}$, as shown in the figure. The polar moments of inertia of the portions $\text{PQ}$ and $\text{QR}$ of the shaft with circular cross-sections are $\text{J}_{1}$ and $\text{J}_{2}$, respectively. The torsional moment reactions at the supports $\mathrm{P}$ and $\mathrm{R}$ are $\mathrm{T}_{\mathrm{P}}$ and $\mathrm{T}_{\mathrm{R}}$, respectively.



If $\mathrm{T}_{\mathrm{P}} / \mathrm{T}_{\mathrm{R}}=4$ and $\mathrm{J}_{1} / \mathrm{J}_{2}=2$, the ratio of the lengths $\mathrm{L}_{1} / \mathrm{L}_{2}$ is

  1. $0.50$
  2. $0.25$
  3. $4.00$
  4. $2.00$
edited by

Please log in or register to answer this question.

Answer: