0 votes 0 votes The value of $\lim \limits_{x\rightarrow \infty } \dfrac{x \:\text{ln}\left ( x \right )}{1+x^{2}}$ is $0$ $1.0$ $0.5$ $\infty$ Calculus gatecivil-2021-set2 calculus limits + – go_editor asked Mar 1, 2021 • recategorized Apr 11, 2021 by Lakshman Bhaiya go_editor 5.3k points answer See all 0 reply