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Recent questions tagged calculus
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GATE2019 CE-1: 1
Which one of the following is correct? $\lim_{x\rightarrow 0} ( \frac{sin4x}{sin2x})=2 $ and $\lim_{x\rightarrow 0} ( \frac{tanx}{x})=1$ $\lim_{x\rightarrow 0} ( \frac{sin4x}{sin2x})=1$ and $\lim_{x\rightarrow 0} ( \frac{tanx}{x})=1$ ... $\lim_{x\rightarrow 0} ( \frac{sin4x}{sin2x})=2$ and $\lim_{x\rightarrow 0} ( \frac{tanx}{x})= \infty$
asked
Feb 14
in
Calculus
by
Arjun
(
2.8k
points)
gate2019-ce-1
calculus
limit
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