0 0 votes $\underset{x \to \infty}{\lim} \bigg( 1+ \dfrac{1}{x} \bigg)^{2x} $ is equal to $e^{-2}$ $e$ $1$ $e^2$ Calculus gate2015-ce-2 calculus limits + – Milicevic3306 1.1k points answer Follow 0 reply
