0 0 votes The area of the region bounded by the parabola $y=x^2+1$ and the straight line $x+y=3$ is $\dfrac{59}{6} \\$ $\dfrac{9}{2} \\$ $\dfrac{10}{3} \\$ $\dfrac{7}{6}$ Calculus gate2016-ce-1 calculus definite-integral area-under-curve + – Milicevic3306 1.1k points answer Follow 0 reply
