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GATE2020CE12
0
votes
The value of $\lim_{x\to\infty}\dfrac{x^25x+4}{4x^2+2x}$ is
$0 \\$
$\dfrac{1}{4} \\$
$\dfrac{1}{2} \\$
$1$
gate2020ce1
engineeringmathematics
limit
calculus
asked
Feb 28
in
Engineering Mathematics
by
jothee
(
2.7k
points)
recategorized
Nov 18
by
soujanyareddy13
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Answer:
B
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