in Calculus recategorized by
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The value of $\displaystyle{} \lim_{x\to\infty}\dfrac{x^2-5x+4}{4x^2+2x}$ is

  1. $0 \\$
  2. $\dfrac{1}{4} \\$
  3. $\dfrac{1}{2} \\$
  4. $1$
in Calculus recategorized by
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1 Answer

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divide by x^2 on numerator and denominator.

you will get ΒΌ

 

option B
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Answer:
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