The cross-section of a small river is sub-divided into seven segments of width $1.5 \mathrm{~m}$ each. The average depth, and velocity at different depths were measured during a field campaign at the middle of each segment width. The discharge computed by the velocity area method for the given data is _____________ $\mathrm{m}^3 / \mathrm{s}$ (round off to one decimal place).
$$\begin{array}{|c|c|c|c|c|}
\hline \text{Segment} & \text {Average depth (D) (m)} & \text{Velocity (m/s) at different depths} \\
& & \mathbf{0.2D} & \mathbf{0 . 6 D} & \mathbf{0 . 8 D} \\ \hline 1 & 0.40 & -- & 0.40 & -- \\
\hline 2 & 0.70 & 0.76 & -- & 0.70 \\\hline 3 & 1.20 & 1.19 & -- & 1.13 \\\hline 4 & 1.40 & 1.25 & -- & 1.10 \\\hline 5 & 1.10 & 1.13 & -- & 1.09 \\\hline 6 & 0.80 & 0.69 & -- & 0.65 \\\hline 7 & 0.45 & -- & 0.42 & -- \\\hline\end{array}$$