0 votes 0 votes For positive integers $p$ and $q$, with $\frac{p}{q} \neq 1,\left(\frac{p}{q}\right)^{\frac{p}{q}}=p^{\left(\frac{p}{q}-1\right)}$. Then, $q^{p}=p^{q}$ $q^{p}=p^{2 q}$ $\sqrt{q}=\sqrt{p}$ $\sqrt[p]{q}=\sqrt[q]{p}$ Others gatecivil-2024-set1 + – admin asked Feb 16 • edited Feb 28 by makhdoom ghaya admin 4.2k points answer See all 0 reply