Method - 1:
$3, \, 7, \, 15, \, x, \, 63, \, 127, \, 255$
$\Rightarrow 2^{2} - 1, \, 2^{3} - 1, \, 2^{4} - 1, \, x, \, 2^{6} - 1, \, 2^{7} - 1, \, 2^{8} - 1$
hence, $x = 2^{5} - 1 = 32 - 1 = 31$
Method - 2:
$3, \, 7, \, 15, \, x, \, 63, \, 127, \, 255$
$\Rightarrow 3, \, 3 \times 2 + 1, \, 7 \times 2 + 1, \, 15 \times 2 + 1, \, 31 \times 2 + 1, \, 63 \times 2 + 1, \, 127 \times 2 + 1$
hence, $x = 15 \times 2 + 1 = 30 + 1 = 31$
Method - 3:
$3, \, 7, \, 15, \, x, \, 63, \, 127, \, 255$
$7-3, \, 15-7, \, x- 15, \, 63-x, \, 127-63, \, 255-127$
$\Rightarrow 7-3, \, 15-7, \, x- 15, \, 63-x, \, 127-63, \, 255-127$
$\Rightarrow 4, \, 8, \, x-15, \, 63-x, \, 64, \, 128$
$\Rightarrow 4 \times 1, \, 4\times 2^{1}, \, x-15, \, 63-x, \, 4 \times 2^{4}, \, 4 \times 2^{5}$
similar G.P. : $4 \times 1, \, 4\times 2^{1}, \, 4 \times 2^{2}, \, 4 \times 2^{3}, \, 4 \times 2^{4}, \, 4 \times 2^{5}$ $(a=4, \, r=2)$
hence, $x - 15 = 4 \times 2^{2}$
$\Rightarrow x - 15 = 4 \times 4$
$\Rightarrow x - 15 = 16$
$\Rightarrow x = 31$