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Method - 1:

$3, \, 7, \, 15, \, x, \, 63, \, 127, \, 255$

$\Rightarrow 2^{2} - 1, \, 2^{3} - 1, \, 2^{4} - 1, \, x, \, 2^{6} - 1, \, 2^{7} - 1, \, 2^{8} - 1$

hence,  $x = 2^{5} - 1 = 32 - 1 = 31$

Method - 2:

$3, \, 7, \, 15, \, x, \, 63, \, 127, \, 255$

$\Rightarrow 3, \, 3 \times 2 + 1, \, 7 \times 2 + 1, \, 15 \times 2 + 1, \, 31 \times 2 + 1, \, 63 \times 2 + 1, \, 127 \times 2 + 1$

hence,  $x = 15 \times 2 + 1 = 30 + 1 = 31$

Method - 3:

$3, \, 7, \, 15, \, x, \, 63, \, 127, \, 255$

$7-3, \, 15-7, \, x- 15, \, 63-x, \, 127-63, \, 255-127$

$\Rightarrow 7-3, \, 15-7, \, x- 15, \, 63-x, \, 127-63, \, 255-127$

$\Rightarrow 4, \, 8, \, x-15, \, 63-x, \, 64, \, 128$

$\Rightarrow 4 \times 1, \, 4\times 2^{1}, \, x-15, \, 63-x, \, 4 \times 2^{4}, \, 4 \times 2^{5}$

similar G.P. :  $4 \times 1, \, 4\times 2^{1}, \, 4 \times 2^{2}, \, 4 \times 2^{3}, \, 4 \times 2^{4}, \, 4 \times 2^{5}$  $(a=4, \, r=2)$

hence,  $x - 15 = 4 \times 2^{2}$

$\Rightarrow x - 15 = 4 \times 4$

$\Rightarrow x - 15 = 16$

$\Rightarrow x = 31$

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