A hydraulic jump is formed in a $5 \: \mathrm{m}$ wide rectangular channel, which has a horizontal bed and is carrying a discharge of $15 \mathrm{~m}^{3} / \mathrm{s}$. The depth of water upstream of the jump is $0.5 \: \mathrm{m}$. The power dissipated by the jump (in $kW$ ) is $\_\_\_\_\_\_$ (rounded off to the nearest integer).
Note:
Acceleration due to gravity $=9.81 \mathrm{~m} / \mathrm{s}^{2}$
Density of water $=1000 \mathrm{~kg} / \mathrm{m}^{3}$
Kinetic energy correction factor $=1.0$
