For the Ordinary Differential Equation ${\large\frac{d^2x}{dt^2}}-5{\large\frac{dx}{dt}}+6x=0$, with initial conditions $x(0)=0$ and ${\large\frac{dx}{dt}}(0)=10$, the solution is

- $-5e^{2t}+6e^{3t}$
- $5e^{2t}+6e^{3t}$
- $-10e^{2t}+10e^{3t}$
- $10e^{2t}+10e^{3t}$