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If $P=\begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}$ and $Q=\begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}$ then $Q^{T}\:P^{T}$ is

  1. $\begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}$
  2. $\begin{bmatrix} 1 & 3 \\ 2 & 4 \end{bmatrix}$
  3. $\begin{bmatrix} 2 & 1 \\ 4 & 3 \end{bmatrix}$
  4. $\begin{bmatrix} 2 & 4 \\ 1 & 3 \end{bmatrix}$
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