in Linear Algebra recategorized by
0 votes
0 votes

If $P=\begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}$ and $Q=\begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}$ then $Q^{T}\:P^{T}$ is

  1. $\begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}$
  2. $\begin{bmatrix} 1 & 3 \\ 2 & 4 \end{bmatrix}$
  3. $\begin{bmatrix} 2 & 1 \\ 4 & 3 \end{bmatrix}$
  4. $\begin{bmatrix} 2 & 4 \\ 1 & 3 \end{bmatrix}$
in Linear Algebra recategorized by
by
11.6k points

Please log in or register to answer this question.

Answer:
Welcome to GATE Civil Q&A, where you can ask questions and receive answers from other members of the community.
Top Users Oct 2022