If the magnetic bearing of the Sun at a place at noon is $\text{S} \; 2^{\circ} \; \text{E},$ the magnetic declination (in $\textbf{degrees}$) at that place is
- $2^{\circ} \; \text{E}$
- $2^{\circ} \; \text{W}$
- $4^{\circ} \; \text{E}$
- $4^{\circ} \; \text{W}$