0 0 votes For a flowing fluid, a dimensionless combination of velocity $(V)$, length scale $(l)$, and acceleration due to gravity $(g)$ would be $\frac{V^{2}}{g l}$ $\frac{V g}{l}$ $\frac{g l^{2}}{V}$ $\frac{l}{V^{2} g}$ Fluid Mechanics gatecivil-2025-set1 fluid-mechanics numerical-answers + – Shubham Sharma 2 427 points answer Follow 0 reply
0 0 votes a akshia answered Nov 10, 2025 akshia 715 points comment Share Follow 0 reply Please log in or register to add a comment.