0 0 votes The solution of the ordinary differential equation $\dfrac{dy}{dx}+2y=0$ for the boundary condition, $y=5$ at $x=1$ is $y=e^{-2x}$ $y=2e^{-2x}$ $y=10.95 e^{-2x}$ $y=36.95 e^{-2x}$ Ordinary Differential Equation (ODE) gate2012-ce ordinary-differential-equation + – Milicevic3306 1.1k points answer Follow 0 reply