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A political party orders an arch for the entrance to the ground in which the annual convention is being held. The profile of the arch follows the equation  $y=2x-0.1x^{2}$ where $y$ is the height of the arch in meters. The maximum possible height of the arch is

  1. $8$ meters
  2. $10$ meters
  3. $12$ meters
  4. $14$ meters

1 Answer

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It is downward facing parabola (x2=−4ay), so at top Slope will be 0.

dy/dx = 0, we get x , put in equation and find y (height).

Final answer is B = 10 meters.
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