Milicevic3306
asked
in Geomatics Engineering
Mar 26, 2018
recategorized
Nov 18, 2020
by soujanyareddy13

0 votes

Following bearings are observed while traversing with a compass

$\begin{array}{rrr} \text{Line} & \text{Fore Bearing} & \text{back Bearing} \\ AB & 126^{\circ} 45’ & 308^{\circ} 00’ \\ BC & 49^{\circ} 15’ & 227^{\circ} 30’ \\ CD & 340^{\circ} 30’ & 161^{\circ} 45’ \\ DE & 258^{\circ} 30’ & 78^{\circ} 30’ \\ EA & 212^{\circ} 30’ & 31^{\circ} 45’ \end{array}$

After applying the correction due to local attraction, the corrected fore bearing of line BC will be

- $48^{\circ} 15’$
- $50^{\circ} 15’$
- $49^{\circ} 45’$
- $48^{\circ} 45’$