0 votes 0 votes If $\text{k}$ is a constant, the general solution of $\dfrac{dy}{dx}-\dfrac{y}{x}=1$ will be in the form of $y=x\text{ ln}(kx)$ $y=k\text{ ln}(kx)$ $y=x\text{ ln}(x)$ $y=xk\text{ ln}(k)$ Ordinary Differential Equation (ODE) gatecivil-2021-set2 ordinary-differential-equation + – go_editor asked Mar 1, 2021 recategorized Mar 13, 2021 by Lakshman Bhaiya go_editor 5.3k points answer See all 0 reply