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GATE2017 CE-1: 27
Milicevic3306
asked
in
Ordinary Differential Equation (ODE)
Mar 26, 2018
recategorized
Mar 11, 2021
by
Lakshman Patel RJIT
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0
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The solution of the equation $\dfrac{dQ}{dt} +Q =1$ with $Q=0$ at $t=0$ is
$Q(t)=e^{-t}-1$
$Q(t)=1+ e^{-t}$
$Q(t)=1 -e^t$
$Q(t)=1- e^{-t}$
gate2017-ce-1
ordinary-differential-equation
Milicevic3306
asked
in
Ordinary Differential Equation (ODE)
Mar 26, 2018
recategorized
Mar 11, 2021
by
Lakshman Patel RJIT
by
Milicevic3306
11.9k
points
answer
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