0 votes 0 votes The solution of the equation $\dfrac{dQ}{dt} +Q =1$ with $Q=0$ at $t=0$ is $Q(t)=e^{-t}-1$ $Q(t)=1+ e^{-t}$ $Q(t)=1 -e^t$ $Q(t)=1- e^{-t}$ Ordinary Differential Equation (ODE) gate2017-ce-1 ordinary-differential-equation + – Milicevic3306 asked Mar 26, 2018 • recategorized Mar 11, 2021 by Lakshman Bhaiya Milicevic3306 11.9k points answer See all 0 reply